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How Can I Take 16-Bit Input In 8086? Quick Answer

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The 8086 has eight more or less general 16-bit registers (including the stack pointer but excluding the instruction pointer, flag register and segment registers). Four of them, AX, BX, CX, DX, can also be accessed as twice as many 8-bit registers (see figure) while the other four, SI, DI, BP, SP, are 16-bit only.

Explanation:
  1. load the value stored into register.
  2. divide the value by 10.
  3. push the remainder into the stack.
  4. increase the count.
  5. repeat the steps until the value of the register is greater than 0.
  6. until the count is greater than zero.
  7. pop the stack.
  8. add 48 to the top element to convert it into ASCII.
2. Addition of 16 bit numbers using 16-bit operation:
  1. Load both the lower and the higher bits of the first number at once.
  2. Copy the first number to another registered pair.
  3. Load both the lower and the higher bits of second number at once.
  4. Add both the register pairs and store the result in a memory location.
Algorithm to Add Two 16 Bit Numbers
  1. Step I : Initialize the data segment.
  2. Step II : Get the first number in AX register.
  3. Step III : Get the second number in BX register.
  4. Step IV : Add the two numbers.
  5. Step V : Display the result.
Problem – Write an assembly language program in 8086 microprocessor to divide a 16 bit number by an 8 bit number.

Program –
MEMORY ADDRESS MNEMONICS COMMENT
0408 INC SI SI <- SI + 1
0409 MOV AX, [SI] AX <- [SI]
040B DIV BL AX <- AX / BL
040D MOV [DI], AX [DI] <- AX
May 23, 2018
How Can I Take 16-Bit Input In 8086?
How Can I Take 16-Bit Input In 8086?

Table of Contents

How do you add 16-bit numbers?

2. Addition of 16 bit numbers using 16-bit operation:
  1. Load both the lower and the higher bits of the first number at once.
  2. Copy the first number to another registered pair.
  3. Load both the lower and the higher bits of second number at once.
  4. Add both the register pairs and store the result in a memory location.
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Which instruction is used to obtain the 16-bit number from 8 bit number?

Problem – Write an assembly language program in 8086 microprocessor to divide a 16 bit number by an 8 bit number.

Program –
MEMORY ADDRESS MNEMONICS COMMENT
0408 INC SI SI <- SI + 1
0409 MOV AX, [SI] AX <- [SI]
040B DIV BL AX <- AX / BL
040D MOV [DI], AX [DI] <- AX
May 23, 2018

8086 Microprocessor 16 bit addition program

8086 Microprocessor 16 bit addition program
8086 Microprocessor 16 bit addition program

Images related to the topic8086 Microprocessor 16 bit addition program

8086 Microprocessor 16 Bit Addition Program
8086 Microprocessor 16 Bit Addition Program

How do you add two 16-bit numbers in assembly language?

Algorithm to Add Two 16 Bit Numbers
  1. Step I : Initialize the data segment.
  2. Step II : Get the first number in AX register.
  3. Step III : Get the second number in BX register.
  4. Step IV : Add the two numbers.
  5. Step V : Display the result.

How many 16-bit segment registers does 8086 have *?

The 8086 has eight more or less general 16-bit registers (including the stack pointer but excluding the instruction pointer, flag register and segment registers). Four of them, AX, BX, CX, DX, can also be accessed as twice as many 8-bit registers (see figure) while the other four, SI, DI, BP, SP, are 16-bit only.

How can we handle the 16-bit data in 8085 microprocessor?

To handle 16-bit data two 8-bit registers can be combined. The combination of two 8-bit registers is called a register pair. The valid register pairs in Intel 8085 are B-C, D-E and H-L. The H-L pair is used to address memories.

How many numbers is 16 bits?

Thus a 16-bit word can be used for positive numbers in the range 0 to 65,535. If negative numbers are required, the most significant bit is used to represent the sign, a 1 representing a negative number and a 0 a positive number; the format used for negative numbers is two’s complement.

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When you do division operation on two 16 bits numbers in 8086 microprocessor which of the following registers are used to store the quotient and remainder?

If the numerator is a 16-bit word and denominator is a byte, then AL and AH registers will store the quotient and remainder.


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What are the instruction set of 8086?

Branch Instructions
Instruction Description
INTO Software interrupts to indicate overflow after arithmetic operation.
LOOP Jump to defined label until CX = 0.
LOOPZ/LOOPE Decrement CX register and jump if CX ≠ 0 and ZF = 1.
LOOPNZ/LOOPNE Decrement CX register and jump if CX ≠ 0 and ZF = 0.

When two 16-bit numbers are multiplied in 8086 the result is stored in?

The multiplication of two 16-bit numbers may result into 32-bit number. So, the result isstored in the DX and AX register.

Which instruction is available for performing 16-bit addition?

As there is only one 16-bit Register in 89C51, 16-bit addition is performed by using ADDC instruction twice, i.e. adding LSD first and MSD next.

What is a 16-bit number?

A 16-bit integer can store 216 (or 65,536) distinct values. In an unsigned representation, these values are the integers between 0 and 65,535; using two’s complement, possible values range from −32,768 to 32,767. Hence, a processor with 16-bit memory addresses can directly access 64 KB of byte-addressable memory.

How does one add two 16-bit numbers using ADD and ADC?

To add two 16 bit registers we first add the two lower bytes together with the ADD command, then we add the two high bytes together and include the carry bit which contains any overflow from the addition of the lower bits. This is accomplished with the Add with Carry command (ADC).

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16 bit addition using 8086 microprocessor

16 bit addition using 8086 microprocessor
16 bit addition using 8086 microprocessor

Images related to the topic16 bit addition using 8086 microprocessor

16 Bit Addition Using 8086 Microprocessor
16 Bit Addition Using 8086 Microprocessor

How many bits is 8086?

8086 Microprocessor is an enhanced version of 8085Microprocessor that was designed by Intel in 1976. It is a 16-bit Microprocessor having 20 address lines and16 data lines that provides up to 1MB storage.

Which of the following register is not 16-bit in 8086?

The 8086 had eight (more or less general) 16-bit registers including the stack pointer, but excluding the instruction pointer, flag register and segment registers.

Are 16-bit registers?

16-bitEdit

The registers found on the 8086 and all subsequent x86 processors are the following: AX, BX, CX, DX, SP, BP, SI, DI, CS, DS, SS, ES, IP and FLAGS. These are all 16 bits wide.

How can I store 16-bit data in register pair?

In this program we are storing the 16-bit numbers into BC, DE and HL pair. We have DAD D instruction which helps to add HL and DE register pair, and store the result into HL pair. After that copy BC to DE, then again perform DAD D to add them. Finally using XCHG we are storing them into DE register pair.

Which is a 16-bit register in 8085 microprocessor?

Stack Pointer: The stack pointer in the 8085 microprocessor is a 16-bit register that stores the address of the top of stack memory. The value of the stack pointer is decremented by 2 in PUSH operation.

How can I add 16-bit number in 8051?

The instruction ADDC (add with carry) is used for 16-bit addition. When adding two 16-bit data operands, we need to be concerned with the propagation of a carry from the lower byte to the higher byte. Program to add 2 16-bit numbers 3CE7H and 3B8DH.

What do you mean by 16-bit microprocessor?

A 16 bit microprocessor is having 16bit register set. It have 16 address and data lines to transfer address and data both. Hence it is 16 address lines. The maximum addresses are 2^16 means 65536.

Which of these is 16bit microprocessor?

In the year 1978, Intel introduced the 16-bit microprocessor 8086 (16-bit bus) and in the year 1979, Intel introduced 8088 (8-bit bus). It had 29,000 transistors. In the year 1981, IBM selected the Intel 8088 for their personal computer (IBM-PC).

What is 16bit compiler?

A 16 bit compiler would compile a program to produce 16 bit machine code, which would typically be meant for a 16 bit machine (16 bit CPU). Similarly for a 32 bit compiler. A 16 bit compiled program would mostly work on a 32 bit machine (backwards compatibility), but not vice versa.

Which 8086 registers is usually used for division operation?

AX – This is the accumulator. It is of 16 bits and is divided into two 8-bit registers AH and AL to also perform 8-bit instructions. It is generally used for arithmetical and logical instructions but in 8086 microprocessor it is not mandatory to have accumulator as the destination operand.


[4.3] MOD REG R/M in 16-bit Instruction | Convert Binary to Assembly | 8086 Microprocessor Tutorial

[4.3] MOD REG R/M in 16-bit Instruction | Convert Binary to Assembly | 8086 Microprocessor Tutorial
[4.3] MOD REG R/M in 16-bit Instruction | Convert Binary to Assembly | 8086 Microprocessor Tutorial

Images related to the topic[4.3] MOD REG R/M in 16-bit Instruction | Convert Binary to Assembly | 8086 Microprocessor Tutorial

[4.3] Mod Reg R/M In 16-Bit Instruction | Convert Binary To Assembly | 8086 Microprocessor Tutorial
[4.3] Mod Reg R/M In 16-Bit Instruction | Convert Binary To Assembly | 8086 Microprocessor Tutorial

What is size of dividend in case of 16-bit division?

After division, the 16-bit quotient goes to the AX register and the 16-bit remainder goes to the DX register. 3. When the divisor is doubleword − The dividend is assumed to be 64 bits long and in the EDX:EAX registers.

What is difference between div and IDIV?

Using Division Instructions:

The DIV instruction divides unsigned numbers, and IDIV divides signed numbers. Both return a quotient and a remainder. Table 4.1 summarizes the division operations. The dividend is the number to be divided, and the divisor is the number to divide by.

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